On the Solutions of the Diophantine Equation $p^x +(p+4k)^y=z^2$ for Prime Pairs $p$ and $p+4k$. Eur. J. Pure Appl. Math. [Internet]. 2021 May 18 [cited 2024 May 3];14(2):471-9. Available from: https://www.ejpam.com/index.php/ejpam/article/view/3947